CALCULUS - HELP
posted by Anonymous .
I am trying to solve 0=1-asin(a) for a, but I have reached a dead end at sin(a) = 1/a. From here I'm not sure what to do.
a=(2k+1/2)π where k=integer
Use the graph of sin(x) to solve for a.
asin(a) does NOT equal 1/sin(a).
asin(a)=x means sin(x)=a
I think I should restate this, I am trying to solve 0=1-a(sin(a). I didn't mean asin to mean arcsin, it's supposed to be a(sin(a)).
Are you doing Calculus or pre-calculus?
I believe that to solve for
requires numerical methods, such as Newton's method, or other approximation methods.
You can also plot sin(x) and 1/x and see where they intersect or as approximations.