# CALCULUS

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Could someone show me the steps to separating the variables in the following differential equation:
dy/dx = (2x+1) / (y+1)? I keep messing it up.

• CALCULUS -

To separate:
dy/dx = (2x+1) / (y+1)
Cross multiply:
(y+1)dy = (2x+1)dx

To solve, integrate both sides
(y^2/2+y) = (x^2+x)+C
where C is an integration constant

• CALCULUS -

Thank you! How would I isolate y by itself to make this a y= expression?

• CALCULUS -

This would be more messy if you are looking for an explicit solution.
You would solve for y as a quadratic equation, and verify that all solutions obtained from the equation are actual solutions.

Most of the time, an implicit solution (where y occurs in more than one term or embedded as a function) is acceptable.

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