math

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what angle between vectors u = 2j+2k & v= 3i+4k
Gracias por ayudarme

  • math -

    u.v = |u| * |v| * cosθ

    cosθ = (6+8)/(2√2)(5) = 14/10√2
    θ = 8.13°

  • math -

    u dot v = |u| |v| cos(theta)

    u dot v = 6

    |u| = 2 sqrt(2)

    |v| = 5

    cos(theta) = 3/[5 sqrt(2)]

  • math -

    Correction u dot v = 8, so

    cos(theta) = 4/[5 sqrt(2)]

  • math -

    but isn't is a three dimensional vectors

  • math -

    my bad. I misread the problem.
    Count Iblis is correct.

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