# Calculus

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Differentiate x^2y^3+x^3y^4=11 implicitly to find dy/dx.

• Calculus -

2xy^3 + 3x^2y^2y' + 3x^2y^4 + 4x^3y^3y' = 0
y' = -(2xy^3 + 3x^2y^4)/(3x^2y^2 + 4x^3y^3)
= -(2y + 3xy^2)/(3x + 4x^2y)
assuming x,y not zero

• Calculus -

Thanks a lot, it makes so much more sense now! :)

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