Calculus
posted by Abhishek .
If y=Root of(logx+root of (logx+root of logx.........infinty)...prove that dy/dx=1/x(2y1)

Calculus 
Steve
y = √(lnx+√(lnx+√(lnx+...)))
y^2 = lnx+√(lnx+√(lnx+...))) = lnx + y
2y y' = 1/x + y'
(2y1)y' = 1/x
y' = 1/(x(2y1))
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