Find the volume of an industrial tank in the form of a horizontal cylinder whose radius si 2.6 yd, and whose length is 8.4 yd Repport your answer to thenearest tenth of a cubic yard and use 3.14
For a cylinder:
V=πr²h
V = pi * r^2 * h
You have posted:
"In regards to my question radius 2.6 yd
length 8.4, 3.14 I used that formula
and somewhere i went wrong ikeep coming up with the answer 68.5776 whichis none of the choices given."
Both of the responses above indicate
V=πr²h
which means that
volume = π × r × r × h
Your answer 68.5776 corresponds to
π × r × h, so it is 2.6 times smaller than the correct answer.
Please try again with the correct formula. If you have problems, please post a follow-up here.
To find the volume of a horizontal cylinder, we can use the formula:
Volume = π * r^2 * h
where π is approximately equal to 3.14, r is the radius of the cylinder, and h is the length of the cylinder.
Given that the radius of the cylinder is 2.6 yards and the length is 8.4 yards, we can substitute these values into the formula:
Volume = 3.14 * (2.6)^2 * 8.4
First, we square the radius:
(2.6)^2 = 6.76
Now, we substitute the squared radius and the length into the formula:
Volume = 3.14 * 6.76 * 8.4
Multiply 6.76 by 8.4:
6.76 * 8.4 = 56.784
Finally, multiply this result by 3.14 to find the volume:
Volume = 3.14 * 56.784
Volume ≈ 178.6552
Rounding it to the nearest tenth of a cubic yard, the volume of the industrial tank is approximately 178.7 cubic yards.