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If f(x) = abs(x - 1) + 1, then f'(1) = ?
Would the answer be 0 or nonexistent. f'(1) = 0/0, so would this be considered nonexistent?

  • Calculus -

    if y = |x-1| + 1
    graph it
    x and y
    0 2
    1 1
    2 2
    straight lines each side of (1,1) with different slopes.
    Thus the derivative is discontinuous (changes from -1 to +1) at x = 1 and is undefined at that point.

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