the sum of 25 consecutive whole numbers is 1000. what is the smallest of the whole numbers?

28

fscv

To find the sum of consecutive whole numbers, you can use the formula for the sum of an arithmetic series:

Sum = (n/2) * (first term + last term)

In this case, we know that the sum is 1000 and we need to find the smallest whole number (first term).

Let's say the smallest whole number is x, and we have 25 consecutive whole numbers. So the last term would be x + 24, since we're adding 24 more numbers to get to the last term.

Now we can plug these values into the formula:

1000 = (25/2) * (x + (x + 24))

Simplifying the equation,
1000 = (25/2) * (2x + 24)

Divide both sides of the equation by (25/2),
40 = 2x + 24

Subtract 24 from both sides of the equation,
40 - 24 = 2x
16 = 2x

Finally, divide both sides of the equation by 2,
16/2 = x
8 = x

Therefore, the smallest whole number is 8.