an ideal gas in a closed inflexible container has a pressure of 6 atm and a temperature of 27 degree celsius . What will be the new pressure of the gas of temperature is decreased to -73 degree celsius?
a) 2 atm
b) 3 atm
c) 4atm
d) 8atm
e) 9atm
plz teach me the method also
Refer to your other post with P and T.
To find the new pressure of the gas when the temperature is decreased, we can use the Combined Gas Law formula, which relates the initial and final pressures and temperatures of the gas.
The Combined Gas Law formula is:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 = Initial pressure
V1 = Initial volume
T1 = Initial temperature (in Kelvin)
P2 = Final pressure
V2 = Final volume
T2 = Final temperature (in Kelvin)
Now, let's solve the problem step by step:
Step 1: Convert the initial temperature from Celsius to Kelvin.
T1 = 27 + 273.15
T1 = 300.15 K
Step 2: Convert the final temperature from Celsius to Kelvin.
T2 = -73 + 273.15
T2 = 200.15 K
Step 3: Plug the given values into the formula and solve for P2:
(P1 * V1) / T1 = (P2 * V2) / T2
(6 * V1) / 300.15 = (P2 * V2) / 200.15
Step 4: Since the container is inflexible (constant volume), V1 = V2, we can simplify the equation:
6 / 300.15 = P2 / 200.15
Step 5: Cross-multiply and solve for P2:
6 * 200.15 = 300.15 * P2
1200.9 = 300.15 * P2
P2 ≈ 4 atm
Therefore, the new pressure of the gas when the temperature is decreased to -73 degrees Celsius is approximately 4 atm.
So, the correct option is (c) 4 atm.