An engine expends 44.0 hp in moving a car along a level track at a speed of 13.9 m/s. How large is the total force acting on the car in the opposite direction of the motion of the car?
Never mind, I figured this one out.
Oh sorry, I copied and pasted the wrong thing.
This question has already been solved.
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To find the total force acting on the car in the opposite direction of motion, we can use the horsepower expended by the engine.
Horsepower (hp) is a unit of power, which is the rate at which work is done. One horsepower is equal to 746 watts.
Given that the engine expends 44.0 hp, we can convert this to watts:
Power (W) = 44.0 hp * 746 W/hp
Now, let's determine the work done by the engine.
Work (W) = Power (W) * time (t)
Since no time is mentioned in the question, we cannot directly calculate work. However, we can use the given speed of the car and the force required to move it at that speed to obtain the answer.
The power expended by the engine is equal to the work done per unit time. In this case, since the car is moving at a constant speed, the work done by the engine is equal to the force exerted by the engine multiplied by the distance traveled by the car.
Let's assume the force acting on the car in the opposite direction of motion is F, and the distance traveled by the car is d.
Work (W) = Force (F) * distance (d)
By rearranging the equation, we can solve for the force:
Force (F) = Work (W) / distance (d)
Now, substituting the values we have:
Force (F) = Power (W) * time (t) / distance (d)
Unfortunately, without the time or the distance traveled, it is not possible to determine the total force acting on the car in the opposite direction of motion.