# physics

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A cyclist is cycling at uniform velocity of 8m/sec for 8 sec then applies brakes and cycle come to rest in next 10 sec. calculate
a)Distance traveled by uniform velocity.
b)distance traveled by non-uniform velocity
c)total distance traveled
d)the average velocity in entire journey

• physics -

(a) s1 =v•t =8•8 =64 m,
(b)
v(final) =v - a•t,
v(final) =0,
a =v/t,
s =v•t - at²/2 =
= v•t - v•t²/2•t =v•t/2=8•8/2=32 m.
(c)
s =s1+s2 = 64+32 = 96 m.
(d)
v(ave) = s/t =96/(8+10) = 5.33 m/s.

• physics -

a)uniform velocity=8m/s t1=8sec t2=10
d=s*t =8*8=64m
b) v=u+at
due to retardation v=u-at
0=u-at
u=at
a=u/t
s=ut+1/2*at^2
s=ut/2
s=64/2=32
c)total disct.=96m
d)avg velocity=total displacement/total time
=96/18=48/9

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