physics

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A cyclist is cycling at uniform velocity of 8m/sec for 8 sec then applies brakes and cycle come to rest in next 10 sec. calculate
a)Distance traveled by uniform velocity.
b)distance traveled by non-uniform velocity
c)total distance traveled
d)the average velocity in entire journey

  • physics -

    (a) s1 =v•t =8•8 =64 m,
    (b)
    v(final) =v - a•t,
    v(final) =0,
    a =v/t,
    s =v•t - at²/2 =
    = v•t - v•t²/2•t =v•t/2=8•8/2=32 m.
    (c)
    s =s1+s2 = 64+32 = 96 m.
    (d)
    v(ave) = s/t =96/(8+10) = 5.33 m/s.

  • physics -

    a)uniform velocity=8m/s t1=8sec t2=10
    d=s*t =8*8=64m
    b) v=u+at
    due to retardation v=u-at
    0=u-at
    u=at
    a=u/t
    s=ut+1/2*at^2
    s=ut/2
    s=64/2=32
    c)total disct.=96m
    d)avg velocity=total displacement/total time
    =96/18=48/9

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