physics
posted by parul .
A cyclist is cycling at uniform velocity of 8m/sec for 8 sec then applies brakes and cycle come to rest in next 10 sec. calculate
a)Distance traveled by uniform velocity.
b)distance traveled by nonuniform velocity
c)total distance traveled
d)the average velocity in entire journey

(a) s1 =v•t =8•8 =64 m,
(b)
v(final) =v  a•t,
v(final) =0,
a =v/t,
s =v•t  at²/2 =
= v•t  v•t²/2•t =v•t/2=8•8/2=32 m.
(c)
s =s1+s2 = 64+32 = 96 m.
(d)
v(ave) = s/t =96/(8+10) = 5.33 m/s. 
a)uniform velocity=8m/s t1=8sec t2=10
d=s*t =8*8=64m
b) v=u+at
due to retardation v=uat
0=uat
u=at
a=u/t
s=ut+1/2*at^2
s=ut/2
s=64/2=32
c)total disct.=96m
d)avg velocity=total displacement/total time
=96/18=48/9
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