A bus travelling at an average speed of 63km/h left a station at 8.15 a.m. A car later left the same station at 9.00 a.m. and caught up with the bus 10.45 a.m. find the average speed of the car.
A bus travelling at an average speed of 63km/h left a station at 8.15 a.m. A car later left the same station at 9.00 a.m. and caught up with the bus 10.45 a.m. find the average speed of the car.
When the two vehicles met, the bus had travelled 63km/h*2.5h=157.5 km, while the car had travelled 1.75 h.
The speed of the car is therefore
157.5km/1.75h=90 km/h.
What are the steps to follow???
Good
To find the average speed of the car, we need to know the distance traveled by both the bus and the car.
Let's calculate the distance traveled by the bus first. The bus traveled for a total of 2 hours and 45 minutes (from 8.15 a.m. to 10.45 a.m.). To convert this time into hours, we divide it by 60: 2 hours and 45 minutes = 2 + 45/60 = 2.75 hours.
The formula to calculate distance is speed multiplied by time. So, for the bus:
Distance = Speed × Time
Distance = 63 km/h × 2.75 hours
Distance = 173.25 km
Now, let's calculate the time taken by the car to catch up with the bus. The car started at 9.00 a.m., so it traveled for a total of 1 hour and 45 minutes (from 9.00 a.m. to 10.45 a.m.). Again, we convert this time into hours: 1 hour and 45 minutes = 1 + 45/60 = 1.75 hours.
Since the car caught up with the bus, the distance traveled by the car is the same as the distance traveled by the bus: 173.25 km.
Finally, we can calculate the average speed of the car:
Average Speed (car) = Distance ÷ Time
Average Speed (car) = 173.25 km ÷ 1.75 hours
Average Speed (car) ≈ 99 km/h
Therefore, the average speed of the car is approximately 99 km/h.