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at 727 degree centigrade,K=3.8*10^-5 for the dissociation of I2 into iodine atoms: I2<->2I. if the original concentration of molecular iodine is 0.20 mol/L calculate the concentration of atomic iodine at equilibrium. check to see if the hundred rule is applicable

  • chemistry -

    ...........I2==> 2I

    K = (I)^2/(I2)
    Substitute from the ICE chart and solve or x. I don't know what the hundred rule is but the answer is within 5% so you can make the approximation that 0.20-x = 0.20.

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