A copper ore consists of 6.32% chalcopyrite, CuFeS2(s). How many grams of ore must be processed to obtain one gram of copper?
Just substitute into what you know. What is percent?
%Cu = (grams Cu/grams ore)*100 =
You know %Cu, you know grams Cu you want, solve for grams ore needed.
The above is incorrect and finds ratio chalcopyrite to ore. Not Cu to ore.
To determine how many grams of ore must be processed to obtain one gram of copper, we need to calculate the percentage of copper in the chalcopyrite compound.
In CuFeS2, there is one copper atom (Cu) for every one formula unit of chalcopyrite. The molecular weight of Cu is 63.55 g/mol.
The percentage of copper in chalcopyrite can be calculated using the molar mass of Cu and the molar mass of chalcopyrite (which includes copper, iron, and sulfur):
Percentage of copper = (Molar mass of Cu / Molar mass of chalcopyrite) x 100
To get the molar mass of chalcopyrite (CuFeS2), we sum the atomic masses of copper (Cu), iron (Fe), and sulfur (S):
Molar mass of chalcopyrite = (Cu atomic mass) + (Fe atomic mass) + 2 x (S atomic mass)
Now we can calculate:
Molar mass of Cu = 63.55 g/mol
Molar mass of chalcopyrite = (63.55 g/mol) + (55.85 g/mol) + 2 x (32.07 g/mol)
After calculating the molar mass of chalcopyrite, we can determine the percentage of copper:
Percentage of copper = (63.55 g/mol / Molar mass of chalcopyrite) x 100
Given that the copper ore consists of 6.32% chalcopyrite, we can calculate the mass of chalcopyrite in one gram of ore:
Mass of chalcopyrite = 6.32% x (mass of ore)
Since we want to find how many grams of ore are required to obtain one gram of copper, we can set up the following equation:
Mass of chalcopyrite / (mass of ore) = 1 g copper / (mass of ore)
Solving for mass of ore yields:
Mass of ore = Mass of chalcopyrite / (1 g copper / (mass of ore)) = 1 / (Percentage of copper) g of ore
Using the above calculations, we can determine the number of grams of ore needed to obtain one gram of copper.