chemistry
posted by Jim .
A chemist makes a “stock” solution of KOH by dissolving 1050.0 grams in enough water to make 1.50 liters of solution. If later on the chemist wants to use this stock solution to make 200.0 mL of 0.10 M KOH, what would the chemist need to do? (Define the steps and show the calculations).

What's the molarity of the stock solution.
mols KOH = 1050 g/molar mass KOH = ?
Then M stock soln = ?mols/1.50L = x.
To dilute use the dilution formula.
c1v1 = c2v2
c = conc
v = volume.
c1 = M of the stock soln from above.
v1 = volume of the stock soln to use(in mL).
c2 = 0.1M
v2 = 200 mL