Precal

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What is the standard form of this parabola:

-2x^2+16x+24y-224=0

Please Help, parabolas are evil.

  • Precal -

    Divide both sides by -2 and complete the square for the x^2 binomial.

    x^2 -8x -12y +112 = 0
    x^2 -8x +16 -12y +96 = 0
    (x -4)^2 -12(y-8) = 0

  • Precal -

    solution:you must be solved for the y of way implicit

    -2x^2+16x-224=-24y
    2x^2-16x+224=24y
    (1/12)x^2-(2/3)x+(224/24)=y

    and solve it

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