Precal
posted by Sam .
What is the standard form of this parabola:
2x^2+16x+24y224=0
Please Help, parabolas are evil.

Divide both sides by 2 and complete the square for the x^2 binomial.
x^2 8x 12y +112 = 0
x^2 8x +16 12y +96 = 0
(x 4)^2 12(y8) = 0 
solution:you must be solved for the y of way implicit
2x^2+16x224=24y
2x^216x+224=24y
(1/12)x^2(2/3)x+(224/24)=y
and solve it