Parabola

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3y^2+24y+72x-96=0

Can anyone put this in standard form: (y - k)2 = 4p(x - h)

All help is greatly appreciated! :)

  • Parabola -

    y^2 + 8y +24x -32 = 0
    y^2 + 8y +16 +24x -48 = 0
    [y -(-4)]^2 = -24(x-2)

    k = -4
    p = -6
    h = 2

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