Chemistry

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What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2 in 115 g of water? The molal freezing point depression constant for water is 1.86°C/m. (Note that when Ca(NO3)2 dissolves in water Ca2+ and NO32- ions are produced).

  • Chemistry -

    mols Ca(NO3)2 = grams/molar mass
    molality = mols/kg H2O
    delta T = i*Kf*m
    You have Kf and m. i for Ca(NO3)2 is 3.
    For freezing point, 0-delta T = f.p.

  • Chemistry -

    should i get -3.34? can't help but feel as though i did wrong

  • Chemistry -

    -3.34 C agrees with my quick calculation.

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