I got NaOH, 7%, and its density is 1,08g/mol. Calculate the molar concentration.
To calculate the molar concentration, you need to know the concentration in terms of percent and the density of the solution.
First, convert the given percent concentration to decimal form by dividing it by 100. In this case, 7% becomes 0.07.
Next, calculate the molarity (molar concentration) using the formula:
Molarity (M) = (percent concentration * density) / molar mass
Where:
- Percent concentration is the concentration in decimal form (0.07)
- Density is the given density of the solution (1.08 g/mL)
- Molar mass is the molar mass of NaOH, which can be calculated by adding the atomic masses of its constituents (Na = 22.99 g/mol, O = 16.00 g/mol, H = 1.01 g/mol)
The molar mass of NaOH is:
22.99 g/mol (Na) + 16.00 g/mol (O) + 1.01 g/mol (H) = 40.0 g/mol
Now, substitute the values into the formula:
Molarity (M) = (0.07 * 1.08 g/mL) / 40.0 g/mol
Molarity (M) = 0.00756 mol/mL
However, the units for molarity are typically expressed in moles per liter (M). Therefore, you need to convert mL to L:
1 mL = 0.001 L
Molarity (M) = 0.00756 mol/mL * 0.001 L/mL
Molarity (M) = 0.00756 mol/L
Therefore, the molar concentration of the NaOH solution is 0.00756 M.