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Find n if t(n) is approximately 10,832 in the geometric sequence with first term 83 and a common ration 1.07

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    83*1.07^n=10832
    1.07^n=10832/83=130.506
    take log and solve for n
    n log(1.07)=log(130.506)
    n= 71.99995 = 72 since 10832 is approximate.

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