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The drawing shows a person (weight W = 581 N, L1 = 0.843 m, L2 = 0.404 m) doing push-ups. Find the normal force exerted by the floor on each hand and each foot, assuming that the person holds this position.


force on each hand

N



force on each foot

N

  • physics -

    without the drawing, ....

  • physics -

    We have vertical and rotational equilibrium.
    All vertical forces are balanced:
    2•N1 +2•N2 –W = 0.
    (N1+N2) = W/2.

    The sum of torques around the feet are
    W•L1 – 2•N2(L1+L2) = 0.

    581•0.843 =2•N2• (0.843+0.404),
    N2 =581•0.843/2• (0.843+0.404) =
    =196.4 N.
    N1+N2 =581/2= 290.5
    N2 = 290.5-196.4=94.1 N

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