# physics

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The drawing shows a person (weight W = 581 N, L1 = 0.843 m, L2 = 0.404 m) doing push-ups. Find the normal force exerted by the floor on each hand and each foot, assuming that the person holds this position.

force on each hand

N

force on each foot

N

• physics -

without the drawing, ....

• physics -

We have vertical and rotational equilibrium.
All vertical forces are balanced:
2•N1 +2•N2 –W = 0.
(N1+N2) = W/2.

The sum of torques around the feet are
W•L1 – 2•N2(L1+L2) = 0.

581•0.843 =2•N2• (0.843+0.404),
N2 =581•0.843/2• (0.843+0.404) =
=196.4 N.
N1+N2 =581/2= 290.5
N2 = 290.5-196.4=94.1 N

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