The length of a rectangle is 15 m longer tan it's width. The perimeter of the rectangle is 74 cm. Find the length and width.
P = 2L + 2W
74 = 2(W + 15) + 2W
74 = 2W + 30 + 2W
74 - 30 = 4W
44 = 4W
11 = W
P = 2L + 2W
74 = 2(W + 15) + 2W
74 = 2W + 30 + 2W
74 - 30 = 4W
44 = 4W
11 = W
P = 2L + 2W
74 = 2(W + 15) + 2W
74 = 2W + 30 + 2W
74 - 30 = 4W
44 = 4W
11 = W
To find the length and width of the rectangle, we can use the information given.
Let's assume the width of the rectangle is represented by "w" (in meters).
According to the information given, the length of the rectangle is 15 meters longer than its width. So, the length can be represented as "w + 15" (in meters).
To find the perimeter, we add the lengths of all four sides of the rectangle. The formula for the perimeter of a rectangle is:
Perimeter = 2 * (length + width)
In this case, the perimeter is given as 74 meters. Substituting the given values into the formula, we get:
74 = 2 * (w + (w + 15))
Simplifying the equation, we have:
74 = 2 * (2w + 15)
37 = 2w + 15
Now, let's solve for "w" by isolating the variable on one side of the equation:
37 - 15 = 2w
22 = 2w
Dividing both sides of the equation by 2, we get:
w = 11
So, the width of the rectangle is 11 meters.
To find the length, we can substitute the value of the width back into the equation for length:
Length = Width + 15
Length = 11 + 15
Length = 26
Therefore, the length of the rectangle is 26 meters and the width is 11 meters.