Physics

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A compact disc spins at 2.8 revolutions per second. An ant is walking on the CD and finds that it just begins to slide off the CD when it reaches a point 3.2 cm from the CD's center.

What is the coefficient of friction between the ant and the CD?

  • Physics -

    2.8 * 2 pi radians/s = 17.6 rad/s
    r = .032 meters

    Ac = w^2 r = (17.6)^2(.032) = 9.9 m/s^2

    m g (mu) = m Ac
    mu g = 9.9
    mu (9.8) = 9.9
    mu is about 1

  • Physics -

    Thank you so much!

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