what is the slope and y intercept of this equation?
x+2=0
Most useful form of straight-line equations is the "slope-intercept" form:
y = m x + b
This is called the slope-intercept form because "m" is the slope and "b" gives the y - intercept
y - intercept = value of y when x = 0
In this case :
y = x + 2
slope = 1
y - intercept = 0 + 2 = 2
y = x + 2 = 0
x = - 2
This point is called x - intercept
value of x when y = 0
eh? The equation was x+2=0
It is a vertical line at x = -2, and has no y-intercept!
To find the slope and y-intercept of the equation, we first need to rearrange it into the standard form of a linear equation, which is y = mx + b. In this case, the given equation is x + 2 = 0.
Step 1: Isolate the variable.
Subtracting 2 from both sides of the equation, we have x = -2.
Step 2: Identify the slope (m).
Since the given equation involves only the independent variable x, there is no coefficient multiplying x. In this case, the coefficient of x is 1, which implies that the slope (m) of the line is 1.
Step 3: Identify the y-intercept (b).
Now that we know the slope (m), we can identify the y-intercept (b). The y-intercept is the point where the line crosses the y-axis, which is represented by the value of y when x = 0.
Plugging x = 0 into the rearranged equation (y = mx + b), we have y = 1(0) + b.
Simplifying, y = b.
From this, we can conclude that the y-intercept (b) is 0.
Therefore, the slope of the equation x + 2 = 0 is 1, and the y-intercept is 0.