a particle moves along the sides ab,bc,cd of a square of sides 25m with a velocity of 25m/s find average velocity of th eparticle
Since it is a square, points a and d are 25 cm apart. I assume they meant to say the speed is 25 m/s along each side, so each side takes 1.0 s to travel. It takes 3.0 s to go from a to d.
In this case the average velocity while travelling along three sides is 25/3 = 8.33 m/s
To find the average velocity of the particle, we need to calculate the total displacement and divide it by the total time taken.
Here's how we can calculate the total displacement:
1. The particle moves along the side AB with a velocity of 25 m/s. The displacement along AB is equal to the length of AB which is 25m. So, the displacement along AB is 25m.
2. The particle then moves along the side BC with a velocity of 25 m/s. The displacement along BC is equal to the length of BC which is 25m. So, the displacement along BC is 25m.
3. Finally, the particle moves along the side CD with a velocity of 25 m/s. The displacement along CD is equal to the length of CD which is 25m. So, the displacement along CD is 25m.
Since the particle moves along each side of the square with the same speed, we can conclude that the total displacement is equal to the perimeter of the square. The perimeter of a square with sides of length 25m is 4 × 25m = 100m.
Now, let's calculate the average velocity:
To find the average velocity, we need to know the total time taken by the particle. If we don't have that information, we cannot accurately calculate the average velocity.
Please provide the total time taken by the particle to move along all the sides of the square, and I will help you calculate the average velocity.