A sample of silver with a mass of 63.3 g is heated to a temperature of 384.4 K
and placed in a container of water at 290.0 K. How much heat is released
into the water?
heat lost by Ag + heat gained by H2O = 0
[mass Ag x specific heat Ag x (Tfinal-Tintial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute and solve for Tfinal which is the only unknown.
Then to find heat released, mass Ag x specific heat x delta T (where delta T = Tfinal-Tinitial for Ag).
To calculate the heat released into the water, we can use the equation:
q = mcΔT
where:
q is the heat transferred
m is the mass of the substance (in this case, water)
c is the specific heat capacity of the substance (in this case, water)
ΔT is the change in temperature of the substance
Given values:
Mass of silver (m1) = 63.3 g
Temperature of silver (T1) = 384.4 K
Temperature of water (T2) = 290.0 K
Specific heat capacity of water (c) = 4.18 J/g°C (or J/gK)
First, we need to calculate the change in temperature:
ΔT = T2 - T1
= 290.0 K - 384.4 K
= -94.4 K
Since the temperature change is negative, we need to take the absolute value:
|ΔT| = 94.4 K
Now, we can calculate the heat released into the water:
q = mcΔT
where:
m is the mass of the water (m2)
Since the mass of the water (m2) is not provided, we cannot proceed with the calculation. Please provide the mass of the water in order to determine the amount of heat released into it.
To find out how much heat is released into the water, we can use the formula for heat transfer:
q = mcΔT
Where:
q = heat transferred
m = mass of the substance
c = specific heat capacity of the substance
ΔT = change in temperature
In this case, the silver is releasing heat into the water, so we need to calculate the heat transferred from the silver to the water.
First, let's find the change in temperature (ΔT). The initial temperature of the silver is 384.4 K, and the final temperature after transferring heat to the water will be 290.0 K. So, ΔT = 290.0 K - 384.4 K = -94.4 K.
The mass of the silver is given as 63.3 g. However, we also need to know the specific heat capacity of silver (c) in order to calculate the heat transfer. The specific heat capacity tells us how much heat energy is required to raise the temperature of a given mass of a substance by 1 degree.
The specific heat capacity of silver is approximately 0.235 J/g·K.
Now we can substitute the values into the formula and calculate the heat transfer:
q = (63.3 g) * (0.235 J/g·K) * (-94.4 K)
Calculating this, we get:
q ≈ -1400 J (rounded to the nearest Joule)
Therefore, approximately -1400 Joules of heat are released into the water. The negative sign indicates that heat is being lost by the silver and gained by the water.