Ralph, Mario, Jack, Laura, and Maria are in the math club. The club advisor will assign students to 3-person teams at the next math team competition. How many different 3-person teams can be formed from these five students?
I got this wrong...here was my answer
5*4*3/(2*1) 60/2 30 teams combination
Uh... (5*4*3)/(1*2*3) = 10
...doesn't it? Google and my calculator say so xD
C(5,3) = (5*4*3)/(1*2*3) = 20
There are 5*4*3 ways to arrange the students, but if the order doesn't matter, all 3! orderings involve the same people.
Thank you!!!!
To find the number of different 3-person teams that can be formed from these five students, you need to use a combination formula.
The combination formula is given by: nCr = n! / (r! * (n-r)!)
Where n is the total number of items (in this case, students), and r is the number of items that need to be selected (in this case, 3-person teams).
Let's calculate the number of combinations:
n = 5 (number of students)
r = 3 (number of students in a team)
Using the combination formula:
5C3 = 5! / (3! * (5-3)!)
= 5! / (3! * 2!)
= (5 * 4 * 3!) / (3! * 2!)
= (5 * 4) / 2
= 10
Therefore, there are 10 different 3-person teams that can be formed from these five students.