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Hello. Please, help me solve this:
Parabola y = ax^2 + bx + c passes through the point (2;-6). Find the values of a, b and c, if vertex of parabola is (4;-10).

  • math -

    let's find the equation in its standard form using the given information

    since the vertex is (4,-10)
    it must be
    y = a(x-4)^2 -10
    but (2,-6) lies on it
    -6 = a(-2)^2 - 10
    4 = 4a
    a = 1
    so y = (x-4)^2 - 10
    y = x^2 - 8x + 16 - 10
    y = x^2 - 8x + 6

    so a=1, b=-8 and c=6

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