KMnO4 + H2SO4 + KNO2---> MnO2 + KNO3 + K2SO4 + H2O

Here is a site that will help you balance this if that is your question.

Here are some hints also.
Mn changes from +7 to +2
N (in KNO2) changes from +3 to +5(in KNO3).
http://www.chemteam.info/Redox/Redox.html

The given chemical equation is:

KMnO4 + H2SO4 + KNO2 ---> MnO2 + KNO3 + K2SO4 + H2O

Step 1: Start by balancing the atoms that appear in only one compound on each side of the equation.

We have:
1 Mn on the left side and 1 Mn on the right side.
1 O on the left side and 2 O on the right side.

To balance the Mn atoms, we need to add a coefficient of 5 in front of MnO2 on the right side. This gives us:

KMnO4 + H2SO4 + KNO2 ---> 5 MnO2 + KNO3 + K2SO4 + H2O

To balance the O atoms, we need to add a coefficient of 4 in front of H2O on the left side. This gives us:

KMnO4 + H2SO4 + KNO2 ---> 5 MnO2 + KNO3 + K2SO4 + 4 H2O

Step 2: Balance the hydrogen (H) atoms by adding a coefficient of 8 in front of H2SO4 on the left side:

KMnO4 + 8 H2SO4 + KNO2 ---> 5 MnO2 + KNO3 + K2SO4 + 4 H2O

Step 3: Balance the potassium (K) atoms by adding a coefficient of 10 in front of KOH on the left side:

KMnO4 + 8 H2SO4 + 10 KNO2 ---> 5 MnO2 + KNO3 + 10 K2SO4 + 4 H2O

Step 4: Double-check that all atoms are now balanced. We have:
Potassium (K): 1 on the left, 20 on the right (10 in KNO2 and 10 in K2SO4)
Manganese (Mn): 1 on the left, 5 on the right (5 in MnO2)
Oxygen (O): 4 on the left, 34 on the right (10 in KNO3, 20 in K2SO4, and 4 in H2O)
Hydrogen (H): 16 on the left, 8 on the right (8 in 4 H2O)
Sulfur (S): 8 on the left, 10 on the right (8 in 8 H2SO4 and 2 in K2SO4)

All the atoms are now balanced, and the balanced equation is:

KMnO4 + 8 H2SO4 + 10 KNO2 ---> 5 MnO2 + KNO3 + 10 K2SO4 + 4 H2O

The balanced chemical equation you provided represents the reaction between potassium permanganate (KMnO4), sulfuric acid (H2SO4), and potassium nitrite (KNO2), which results in the formation of manganese dioxide (MnO2), potassium nitrate (KNO3), potassium sulfate (K2SO4), and water (H2O).

To determine how many moles of each compound are involved in the reaction, we need to use the coefficients in the balanced equation. The coefficients represent the ratio of moles of each compound involved in the reaction.

Here is the breakdown of the balanced chemical equation:

1 KMnO4 + 1 H2SO4 + 1 KNO2 -> 1 MnO2 + 1 KNO3 + 1 K2SO4 + 1 H2O

In this equation, the coefficients in front of each compound show the number of moles of that compound involved in the reaction.

To calculate the number of moles of each compound, you need to know the mass or volume of the substances involved. The molar mass of each substance can be used to convert between moles and grams.

Let's say we have 10 grams of KMnO4:

1. Calculate the number of moles of KMnO4:
- Find the molar mass of KMnO4:
- K (potassium) has a molar mass of 39.1 grams/mole.
- Mn (manganese) has a molar mass of 54.9 grams/mole.
- O (oxygen) has a molar mass of 16.0 grams/mole.
- Add up the molar masses:
- 39.1 + (54.9 + 4 * 16.0) = 39.1 + (54.9 + 64.0) = 158.0 grams/mole.
- Calculate the number of moles:
- Number of moles = Mass / Molar Mass
- Number of moles = 10 grams / 158.0 grams/mole = 0.063 moles.

2. Use the coefficients from the balanced equation to find the number of moles of other compounds involved in the reaction:
- Since the coefficients for all compounds are 1, we know that the number of moles of each compound is the same as the number of moles of KMnO4.
- Therefore, the number of moles of H2SO4, KNO2, MnO2, KNO3, K2SO4, and H2O is also 0.063 moles.

This demonstrates how to calculate the number of moles of each compound involved in the reaction based on the given balanced chemical equation.