# trig

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write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x), sin6x-sin2x

• trig -

sinAcosB = 1/2 (sin(A+B) + sin(A-B))

Looks like 1/2(sin6x+sin2x)

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