trig
posted by kate .
write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2xcos6x), 1/2(sin6x+sin2x), sin6xsin2x

sinAcosB = 1/2 (sin(A+B) + sin(AB))
Looks like 1/2(sin6x+sin2x)
Respond to this Question
Similar Questions

trig
sinx = 4/5 and x terminates in Quadrant II Find sin2x and cos2x How to get the answers, which are sin2x = 24/25, cos2x = 7/25? 
trig
cotx = 2 and 0 less than or equal to x less than or equal to pi Find sin2x and cos2x How to get the answers of sin2x = 4/5, cos2x = 3/5? 
Trigcheck answer
Solve the equation of the interval (0, 2pi) cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came up with cos²x=1cos²x Ended up with 2cos²x=1 Would the answer be cos²x=1/2? 
Calculus
Solve identity, (1sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²xsin²x)/(1+2sinxcosx) =(cos²x(1cos²x))/(1+2sinxcosx) and the right side just goes in circle. May I get a hint to start off? 
Trig
Simplify: (cosx + cos2x + cos3x + cos4x + cos5x + cos6x) / (sinx + sin2x + sin3x + sin4x + sin5x + sin6x) into a single Cotangent function. Using the sumtoproducts, I was able to get remove some of the addition in attempts to get … 
trig
(sec6x+sin2x)/(sin6xsin2x)=tan4xcot2x 
trig
write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2xcos6x), 1/2(sin6x+sin2x), sin6xsin2x 
trig
write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2xcos6x), 1/2(sin6x+sin2x), sin6xsin2x 
trigonometry
Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+sin2xcos2x ive tried this problem so many times I need help with it... 
Maths
Prove that cos3x/cosxcos6x/cos2x=2(cos2xcos4x)