Calculus
posted by Liz .
Find the third Derivative of
f(x)=x(3x7)^3
The answer is 3x1134 but I attempted the problem multiple times and I keep ending up with 648x1134. What am I doing wrong?

rather than using the product rule and repeated simpification, I thought I would expand the whole thing
f(x) = x(3x7)^3
= x[ (3x)^3 + 3(3x)^2 (7) + 3(3x)(7)^2 + (7)^3 ]
= x[ 27x^3  189x^2 + 441x  343]
= 27x^4  189x^3 + 441x^2  343x
f'(x) = 108x^3  576x^2 + 882x
f''(x) = 324x^2  1152x + 882
f'''(x) = 648x  1152
btw, Wolfram agrees with my answer
I kept feeding the previous derivative back in..
here is the last step
http://www.wolframalpha.com/input/?i=18%2818x%5E2++63x+%2B+49%29 
f = x(3x7)^3
f' = (3x7)^3 + 9x(3x7)^2
f'' = 9(3x7)^2 + 9(3x7)^2 + 54x(3x7)
= 18(3x7)^2 + 54x(3x7)
f''' = 108(3x7) + 54(3x7) + 162x
= 162(3x7) + 162x
= 162(4x7)
= 648x  1134
We have a winner! Book is wrong.