Chemistry

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The pH of a 0.010 M aqueous solution of a weak monoprotic acid, HX, is 4.5. What is the value of the acid ionization constant?

  • Chemistry -

    pH = -log(H^+) = 4.5
    (H^+) = 3.16E-5

    .............HX ==> H^+ + X^-
    I..........0.10M...0.....0
    C............-x.....x.....x
    E..........0.10-x...x.....x

    x = 3.16E-5. Substitute into Ka expression and solve for Ka.

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