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Calculus

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determine the angle between the planes 2x + 2y + 7z = 8 and 3x - 4y + 4z = 5

  • Calculus -

    let Ø be the angle between their normals

    (2,2,7)∘(3,-4,4) = √57√41cosØ
    cosØ = (6 - 8 + 28)/(√57√41)
    Ø = appr. 57.5°

    so the two planes form an angle of 180-57.5 or 122.5°

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