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the magnetic force on a straight 0.15m segment of wire carrying a current of 4.5 A is 1.0 N. What is the magnitude of the component of the magnetic field that is perpendicular to the wire?

  • physics -

    F = Bx*I*L
    where Bx is the magnetic field normal to the wire.

    Bx = F/(I*L) = 1.0/(4.5*0.15)
    = 1.48 Tesla

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