Point X and Y are 30.0 mm and 58.0 mm away from a charge of +8.0 C.

a. How much work must be done in moving a +2.0 C charge from point Y to point X?
b. What is the potential difference between points X and Y?
c. Which point is at the higher potential?

My goodness! Twelve physics posts in a row under three different names. I'm so sorry you know nothing about any of these problems! Or are you just dumping your homework on us, hoping someone will help you cheat?

m nt good at physics .....i don't understand physics so well .....i try to do the problems but they don't make sense at all .....so i ask it here ...and wen someone helps me ...i understand them and then only write them ......m not cheating .....i just need help to understand it .......

To answer the given questions, we need to use the concept of electrostatics and electric potential.

a. The work done in moving a charge between two points is given by the formula:

Work = Q * ΔV

Where:
- Q is the charge being moved (in this case, +2.0 μC)
- ΔV is the potential difference between the two points (which we'll calculate later)

Since we know the charge (Q) and have to calculate the work, we need to find the potential difference (ΔV) between points X and Y.

b. The potential difference (ΔV) between two points is given by the formula:

ΔV = k * (Q / r)

Where:
- k is the electrostatic constant (9 x 10^9 N m²/C²)
- Q is the charge creating the electric field (+8.0 μC)
- r is the distance between the charge and the point in question (30.0 mm or 58.0 mm)

We'll calculate the potential difference between points X and Y using this formula.

c. The higher potential will be at the point with a greater potential difference from the given charge. We'll compare the potential differences at points X and Y to determine which has a higher potential.

Let's calculate the answers to each part one by one.

a. Work in moving the charge from Y to X:
To calculate the work, we'll first calculate the potential difference (ΔV), and then multiply it by the charge (Q).
Following the given steps, we'll calculate ΔV using the formula:

ΔV = k * (Q / r)

ΔV = (9 x 10^9 N m²/C²) * (8.0 μC / 58.0 mm)

Note: Before substituting the values, we need to convert the distance (58.0 mm) to meters.

Using 1 meter = 1000 mm, we find:

ΔV = (9 x 10^9 N m²/C²) * (8.0 x 10^-6 C) / (58.0 x 10^-3 m)

Simplifying the equation, we get:

ΔV = 1.24 x 10^5 V

Now, let's calculate the work using the formula:

Work = Q * ΔV

Work = (2.0 μC) * (1.24 x 10^5 V)

Simplifying the equation, we get:

Work = 2.48 x 10^5 μJ

Therefore, the work done in moving a +2.0 μC charge from point Y to X is 2.48 x 10^5 μJ.

b. Potential difference between points X and Y:
We already calculated the potential difference (ΔV) between points X and Y in the previous step. It is 1.24 x 10^5 V.

Therefore, the potential difference between points X and Y is 1.24 x 10^5 V.

c. Higher potential point:
To determine which point has a higher potential, we compare the potential differences at points X and Y.
Since the potential difference at point X is higher than at point Y (1.24 x 10^5 V > 0 V), point X is at a higher potential.

In summary:
a. The work done in moving a +2.0 μC charge from point Y to X is 2.48 x 10^5 μJ.
b. The potential difference between points X and Y is 1.24 x 10^5 V.
c. Point X is at the higher potential.