calculus
posted by shirlee .
f(x)=(2x1)^2(x^29)
find f'(x)=0
So first derivative:
f'(x)=16x^36x^270x+36
0 = 16x^36x^270x+36
Ok.. I know I should factor it somewhere.. I just couldn't see where..
Thanks!

f'(x) should read:
16x^312x^270x+36
and f'(2)=0
From there, you can find the other factors.