posted by ryan

the ph of a .030M C2H5 COOH solution is 3.20. What is this acids Ka?

  1. DrBob222

    Convert pH to H^+).
    pH = -log(H^+)
    3.20 = -log(H^+)
    I get 6.3E-4 but you should confirm that.
    .....C2H5COOH ==> H^+ + C2H5COO^-

    Ka = (H^+)(C2H5COO-)/(C2H5COOH)
    Substitute from the ice chart and solve for Ka. Check all of those numbers to make sure I punched the right numbers.

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