Chemistry
posted by Andrew .
For the reaction below, Kp = 1.16 at 800.°C.
CaCO3(s) CaO(s) + CO2(g)
If a 25.0g sample of CaCO3 is put into a 10.2L container and heated to 800.°C, what percent of the CaCO3 will react to reach
equilibrium?

CaCO3(s) ==> CaO(s) + CO2
I...25.0.......0.........0
C.......................x
E........................x
Kp = pCO2 = 1.16
Therefore, p CO2 = 1.16 atm. Plug that into PV = nRT and solve for n.
Convert 25.0 g CaCO3 to mols, then calculate the percent decomposed. 
34%