An 21.0 , 12.0 , and 5.0 resistor are connected in series with an emf source. The current in the 12.0 resistor is measured to be 4.00 A.
Question?
To find the current in the other resistors, we can use Ohm's Law, which states that the current flowing through a resistor is equal to the voltage across the resistor divided by its resistance.
In this case, we are given the current in the 12.0 Ω resistor (4.00 A). To find the voltage across the 12.0 Ω resistor, we can use Ohm's Law: V = I * R, where V is the voltage, I is the current, and R is the resistance. Plugging in the known values, we can find the voltage across the 12.0 Ω resistor.
V = 4.00 A * 12.0 Ω = 48.0 V
Now, since the resistors are connected in series, the same current flows through all the resistors. Therefore, the current in the 21.0 Ω resistor and the 5.0 Ω resistor will also be 4.00 A.