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Give the slope and y-intercept of the given line.
1.2x-3y=6
2. y=-2x
3. y=3
4. x+2=0

Find the slope of the line that is a) parallel and b) perpendicular to the given line.
1. x=-8
2. y=10

  • math -

    1.


    2 x - 3 y = 6

    - 3 y = 6 - 2 x Divide both sides by - 3

    y = 6 / - 3 - 2 x / - 3

    y = - 2 + 2 x / 3

    y = ( 2 / 3 ) x - 2


    Slope 2 / 3


    y - intercept

    2 * 0 - 3 y = 6

    - 3 y = 6 Divide both sides by - 3

    y = 6 / - 3 = - 2


    2.


    y = - 2 x

    Slope - 2


    y - intercept


    y = - 2 * 0 = 0


    3.


    y = 3

    y = 3 for all value of x

    This line is parallel with x axis

    Slope = tan 180 ° = 0


    y - intercept :

    y = 3


    4.


    x + 2 = 0

    x = - 2

    x = - 2 for all value of y


    This line is parallel with y axis

    Slope = tan 90 ° = infinity


    y - intercept not exist



    1.


    x = - 8

    x = - 8 for all value of y

    This line is parallel with y axis

    Slope = tan 90 ° = infinity


    a)

    Parallel line slope = tan 90 ° = infinity

    b)

    Normal line slope = tan ( 90 ° - 90 ° ) = tan 0 = 0


    2.


    y = 10


    y = 10 for all value of x

    This line is parallel with x axis

    Slope = tan 180 ° = 0


    a)

    Parallel line slope = tan 180 ° = 0
    b)

    Normal line slope = tan ( 180 ° - 90 ° ) = tan 90 ° = infinity

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