how many atoms of oxygen are present in 30 g of glucose
To determine the number of atoms of oxygen present in 30 g of glucose, we need to follow these steps:
Step 1: Find the molar mass of glucose (C6H12O6).
The molar mass of glucose can be calculated by summing up the atomic masses of its constituent elements: carbon (C), hydrogen (H), and oxygen (O). The atomic masses (in g/mol) are usually listed on the periodic table.
C: 12.01 g/mol
H: 1.01 g/mol
O: 16.00 g/mol
Molar mass of glucose = (6 * C) + (12 * H) + (6 * O)
= (6 * 12.01) + (12 * 1.01) + (6 * 16.00)
= 72.06 + 12.12 + 96.00
= 180.18 g/mol
Step 2: Calculate the number of moles of glucose.
Using the formula:
Number of moles = Mass (g) / Molar mass (g/mol)
Number of moles of glucose = 30 g / 180.18 g/mol
≈ 0.166 moles
Step 3: Determine the number of oxygen atoms.
In one molecule of glucose (C6H12O6), there are 6 atoms of carbon (C), 12 atoms of hydrogen (H), and 6 atoms of oxygen (O).
To calculate the number of oxygen atoms, we multiply the number of moles of glucose by the Avogadro's number, which represents the number of particles in one mole of substance (6.022 x 10^23).
Number of oxygen atoms = Number of moles * Avogadro's number
Number of oxygen atoms = 0.166 moles * (6.022 x 10^23 atoms/mol)
≈ 9.995 x 10^22 atoms
Therefore, approximately 9.995 x 10^22 atoms of oxygen are present in 30 g of glucose.