Pam has a mass of 33.0 kg and she is at rest on smooth, level, frictionless ice. Pam straps on a rocket pack. The rocket supplies a constant force for 15.0 m and Pam acquires a speed of 60.0 m/s.
(a) What is the magnitude of the force?
1 N
(b) What is Pam's final kinetic energy?
2 59400
- i got th3e second answer need help with the first!
a =v²/2•s = (60)²/2•15 = 120 m/s².
F= m•a = 33•120 = 3960 N.
KE = m•v²/2 = 33•(60)²/2 =59400 J.
To find the magnitude of the force exerted by the rocket pack, we can use Newton's second law of motion, which states that force is equal to the mass of an object multiplied by its acceleration.
In this case, we know that Pam has a mass of 33.0 kg and she acquires a speed of 60.0 m/s after traveling a distance of 15.0 m. Since she started from rest, her initial velocity is 0 m/s.
We can use the equation of motion: v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.
Plugging in the given values, we have:
(60.0 m/s)^2 = (0 m/s)^2 + 2a(15.0 m)
Simplifying the equation, we get:
3600 m^2/s^2 = 30 a m
Rearranging the equation to solve for acceleration (a), we divide both sides by 30:
a = 3600 m^2/s^2 / 30 m
Simplifying further, we find:
a = 120 m/s^2
Now, we can calculate the magnitude of the force (F) using Newton's second law of motion:
F = ma
Plugging in the values we have:
F = (33.0 kg)(120 m/s^2)
Calculating the equation, we find:
F = 3,960 N
Therefore, the magnitude of the force exerted by the rocket pack on Pam is 3,960 N.