Math
posted by Hannah .
One bag contains 5 red marbles, 4 blue marbles, and 3 yellow marbles, and a second bag contains 4 red marbles, 6 blue marbles, and 5 yellow marbles. If Lydia randomly draws one marble from each bag, what is the probability that they are both not yellow?

The two draws are independent.
So the probability of getting a yellow in both bags is the product of the probability of getting a yellow in each bag.
P1(Y)=3/12
P2(Y)=5/15
So
P(Y,Y)=P1(Y)*P2(Y) 
ryrrr7o

1/12

4

The question asks the opposite... not yellow.
so 9/12 * 10/15 = .75 * .666 = 50% 
Andrew has it right.