In the figure the coefficient of static friction between mass (MA) and the table is 0.40, whereas the coefficient of kinetic friction is 0.28 ?

part a) What minimum value of (MA) will keep the system from starting to move?

part b) What value of(MA) will keep the system moving at constant speed?

physics - Elena, Tuesday, May 8, 2012 at 1:35pm
Block on the table m(A) = m1,
block on the cord m2,
the coefficient of static friction is k1=0.4,
the coefficient of kinetic friction is k2 =0.28
(a)
Block A:
T = F(fr) = k1 •N = k(s) • m1 •g,
Block B: T = m2•g.
k1 • m1 •g= m2•g,
m1 = m2/k(s) = m2/0.4.

(b)
Block A:
T = F(fr) = k2 •N = k2 • m1 •g,
Block B:
T = m2•g.
k2• m1 •g= m2•g,
m1 = m2/k2 = m2/0.28.

- thanks for the help, i am having a lot of trouble with this problem, what is m2 ?

nvm i got the answer, i was just cofused on how you explain it. Thank you . I got 5 for part a and for part b got 7.14. thank you

To determine the value of m2, we need more information from the problem. Please provide the necessary information, such as the masses of block A and block B, or any other relevant data.

To find the value of m2, we need more information from the problem statement or the figure. The value of m2 represents the mass of the block on the cord. It is usually given in the problem or you need to calculate it based on the given information. Look for any additional information provided in the problem that can help you find the value of m2, such as the masses of the blocks or any other relevant information.