If there are 8.8 moles of h2 and co2 in a 500 ml container at equilibrium how many moles of co and h2o would be present?
Is your subject chemistry?
Yes chemistry
You need an equation. It needs to be balanced. You need a Kp or Kc.
To determine the number of moles of CO and H2O present at equilibrium, we need to know the balanced chemical equation for the reaction involving H2 and CO2.
Let's assume the balanced chemical equation is:
H2 + CO2 ⇌ CO + H2O
The equation tells us that for each mole of H2 reacted, one mole of CO and one mole of H2O are produced.
Given that there are 8.8 moles of H2 and CO2 in the container, we can conclude that there are 8.8 moles of H2 reacted. Therefore, there will be an equal number of moles of CO and H2O produced.
Thus, at equilibrium, there will be 8.8 moles of CO and 8.8 moles of H2O present in the 500 ml container.