advanced functions grd 12
posted by kerry
im not sure wheer to start and how to do solve this problem
solve: cosX(2sinX3^1/2)=0 ,0<(or equal to)X<(or equal to)2(pie sign)

Reiny
I read that as
cosx(2sinx  √3) = 0 , 0 ≤ x ≤ 2π
since it is already factored we can say
cosx=0 OR sinx = √3/2
if cosx = 0
x = π/2 or x = 3π/2 , (90° or 270°)
if sinx = √3/2
then x must be in quadrants I or II
x = π/3 or x = 2π/3 , (60° or 120°) 
kerry
i didn't know how to put the root in so i converted it by adding in the 1/2 exponent! thank you :)
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