posted by Amy
Here is my question and I,m hoping I worked the problem out correctly.
A 10-g mass of krypton occupies 15.0 L at a pressure of 210 kPa. Find the volume of the krypton when the pressure is increased to 790 kPa.
V2 = V1 x P1/P2
V2 = 15.0 L x 210 kPa/790 kPa = 3.98 L or rounded 3.99 L
I want to thank DrBob222, KingChemist and Butler Raines for your help with my Chemistry!
It looks ok to me? What did you do? Get a consortium of three people to answer this? You must have used another board; neither KingChemist nor Butler Raines post on Jiskha.