A hockey puck moving at 28 m/s is caught by an 80.00 kg man who was at rest. The man and puck move together after the collision. The puck's mass is 0.16 kg. What is the final velocity?

A. 1.36 m/s

B. 0.06 m/s
C. 8 m/s
D. 4.5 m/s

0.06 m/s

To find the final velocity of the man and the puck after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

First, let's find the initial momentum of the system before the collision. The momentum of an object is given by the product of its mass and velocity.

Initial momentum of the puck = mass of the puck × velocity of the puck
= 0.16 kg × 28 m/s
= 4.48 kg·m/s

Since the man was initially at rest, his initial momentum is zero.

Therefore, the initial momentum of the system is 4.48 kg·m/s.

After the collision, both the man and the puck move together. Let's assume their final velocity is vf.

Final momentum of the system = (mass of the man + mass of the puck) × final velocity
= (80.00 kg + 0.16 kg) × vf
= 80.16 kg × vf

Since momentum is conserved, the initial momentum of the system is equal to the final momentum:

Initial momentum = Final momentum
4.48 kg·m/s = 80.16 kg × vf

Now we can solve for vf:

vf = 4.48 kg·m/s / 80.16 kg
vf ≈ 0.056 m/s

Therefore, the final velocity of the man and the puck after the collision is approximately 0.056 m/s.