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When a ball is thrown in the air, the height h of a ball in feet t seconds after the ball is thrown in the air, is given by the equation height = 25t–16t²

Use the quadratic equation to determine how many seconds goes by before the ball hits the ground?

  • math HELP -

    When the ball hits the ground height be zero.

    25 t - 16 t ^ 2 = 0

    t ( 25 - 16 t ) = 0

    This equation will be zero when t = 0

    OR

    25 - 16 t = 0


    25 - 16 t = 0 Add 16 to both sides

    25 - 16 t + 16 t = 0 + 16 t

    25 = 16 t Divide both sides by 16

    25 / 16 = t

    t = 25 / 16


    When t = 0 ball does not fly.

    So solution are :

    t = 25 / 16 seconds

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