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The half life of phosphorus -32 is 14.3 days. What percentage of an original samples radioactivity remains after 57.2 days?

  • chemistry -

    k = 0.693/t1/2/sub>
    ln(No/N) = kt
    No = 100 (for convenience)
    N = ?
    t = 57.5 days
    k from above.
    Then (N/No)*100 = %remaining.

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